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"Day 54 of My Learning Journey: Setting Sail into Data Excellence! Today's Focus: Maths for Data Analysis ( Perm & Comb - 9)

PERMUTATION AND COMBINATION - 9

Alike Objects

Permutation of Alike Objects :-

Arrangement :-

Q1. 4 objects ( alike ) in how many ways can you arrange them ?

AAAA only in 1 way.

Explanation :-

No. of arrangements if they are different = 4!
But in this case all are alike so, = 4! / 4! = 1

Q2. 3 objects and other 2 objects( alike ) in how many ways can you arrange them ?

AAABB

Explanation :-

No. of arrangements if they are different = 5!
But in this case all are alike so, = 5! / 3! * 2!

Q3.A,A,B,B,B,C,C,D,D,D,D
In how many ways can you arrange them ?

Explanation :-

No. of arrangements if they are different = 11!
But in this case all are alike so, = 11! / 2! * 3! * 2! * 4!

WHY WE DIVIDE to get the correct answer because they are not the same.

Combination of Alike Objects :-

Selection :-

Q1. consider some objects
A,A,B,B,B,C,C?

IN HOW MANY WAYS WE CAN SELECT ONE OBJECT ?

NO. OF UNIQUE OBJECTS
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IN HOW MANY WAYS WE CAN SELECT TWO OBJECTS ?

Bucket method :- 
 1 bucket - AA 
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2 bucket - BBB
3 bucket - CC

WE HAVE TO USE A BUCKET METHOD. 
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BOTH DIFFERENT - 3c2
BOTH ALIKE - 3c1

3C2 MEANS there are 3 buckets and we need both to be different so, at least we need to select 2 buckets where we can select different objects.

IN HOW MANY WAYS WE CAN SELECT THREE OBJECTS ?

Bucket method :-
1 bucket - AA
2 bucket - BBB
3 bucket - CC

WE HAVE TO USE A BUCKET METHOD. 
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ALL DIFFERENT - 3c3
ONE ALIKE TWO DIFFERENT - 3c1 * 2c1
ALL SAME - 1

This is the last CLASS for Permutation and Combination.

From Today Onwards I will be Starting Probability.

Feel free to share this post to enhance awareness and understanding of these fundamental concepts in statistical analysis!

馃檹 Thank you all for your time and support! 馃檹

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